What will be the cost of covering the white portion in figure 13.21 with a silver foil if the rate is Rs. 100 per m2? (π = 3.14)

Figure 13.21
Given side of a square (a) = 12 cm
Radius of each sector (r) = 12 cm
since it is square the angle (θ) = 90o
let divide the square into 2 parts. (BAPC, DAQC)
Area of part – 1
The area of the sector BAPC = ![]()
=
× 122 × 90
= 113.04 cm2
Area of square = a2
= 122
= 144 cm2
Area of part 1 (APC) = Area of square - The area of the sector BAPC
= 144 – 113.04
= 30.96 cm2
∵ The shapes are identical
The area of part 2 (AQC) = 30.96 cm2
Area of the colored region = area of PART 1+ area of part 2
= 30.96 + 30.96
= 61.92 cm2
Cost for covering 1 m2 silver foil = 100
Cost for covering 61.92 m2 silver foil = 61.92 × 100
= 6192
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