A circle is inscribed in APQR where m∠Q = 90, PQ = 8 cm and QR = 6 cm. Find the area of the blue coloured region shown in figure 13.29. (
= 3.14)

Figure 13.29
from the given figure
PQR is a right-angle triangle
PQ = 8 cm
QR = 6 cm
PR2 = PQ2 + QR2
PR2 = 82 + 62
PR = √100 = 10 cm
Radius of the incircle (r) =
=
=
= 2 CM
area of coloured region = Area of triangle - area of circle
=
× PQ × QR - π r2
=
× 8 × 6 - π 22
= 24 – 12.566
= 11.433 cm2
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