If the pth and qth terms of a G.P. are q and p respectively, show that its (p + q)th term is 
The nth term of GP is given by tn = arn-1 where a is the first term and r is the common difference
pth term is given as q
⇒ tp = arp-1
⇒ q = arp-1
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qth term is given as p
⇒ tq = arq-1
⇒ p = arq-1
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Using (a) and (b)
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(p + q)th term is given by
⇒ tp+q = arp+q-1
⇒ tp+q = (arp-1)rq
But tp = arp-1 and the pth term is q
⇒ tp+q = qrq
But ![]()







Hence proved the (p + q)th term is
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