Let Sn denote the sum of the cubes of the first n natural numbers and sn denote the sum of the first n natural numbers. Then
equals.
Given that:
Sn = sum of the cubes of first n natural numbers
sn = Sum of the first n natural numbers
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Let Tn be the nth term of the above series
…(i)
We know that,
Sum of cubes of first n natural numbers

and sum of first n natural numbers
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∴, eq. (i) becomes

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Now, sum of the given series
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Hence, the correct option is (a)
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