Using the principle of mathematical induction, prove each of the following for all n ϵ N:

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To Prove:
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Let us prove this question by principle of mathematical induction (PMI)
Let P(n): ![]()
For n = 1
LHS = ![]()
RHS = ![]()
Hence, LHS = RHS
P(n) is true for n = 1
Assume P(k) is true
=
……(1)
We will prove that P(k + 1) is true
RHS = ![]()
LHS = ![]()
= ![]()
[ Writing the second last term ]
=
[ Using 1 ]
= ![]()
= ![]()
= ![]()
( Splitting the numerator and cancelling the common factor)
= RHS
LHS = RHS
Therefore, P (k + 1) is true whenever P(k) is true
By the principle of mathematical induction, P(n) is true for×
where n is a natural number
Hence proved.
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