If the sum of a certain number of terms of the AP 27, 24, 21, 18, …. is –30, find the last term.
To Find: Last term of the AP.
Let the number of terms be n.
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⇒n[54 - 3n + 3] = - 60
⇒3n2 - 57n - 60 = 0
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Either n = 20 or n = - 1 (n cannot be negative)
Therefore n = 20
Also,
, where l is the last term.
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⇒ - 30 = 270 + 10l
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⇒l = - 30
The last term is - 30.
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