A man saved ₹660000 in 20 years. In each succeeding year after the first year, he saved ₹2000 more than what he saved in the previous year. How much did he save in the first year?
Given: -
Amount saved by a man in 20 years is Rs.660000.
Let the amount saved by him in the first year be
.
In every succeeding year, he saves Rs.2000 more than what he saved in the previous year.
Increment of saving of the year when compared last year is Rs.2000
Hint: - The above information looks like the savings are in Arithmetic Progression.
Amount saved in first year = a
Common difference = d = ₹2000
Total number of years = n = 20
The total amount saved in 20 years is ₹660000
Sum of n terms in an A.P ![]()
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a = 14000
∴ In the first year, he saved ₹14000.
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