In a ∆ABC, if
, show that the triangle is isosceles.
Given: ![]()
Need to prove: ∆ABC is isosceles.
![]()
⇒ ![]()
⇒
[Squaring both sides]
⇒ ![]()
We know, ![]()
Therefore, ![]()
So,
⇒ ![]()
⇒ ![]()
That means a and b sides are of same length. Therefore, the triangle is isosceles. [Proved]
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