In a ∆ABC, if
, show that the triangle is right-angled.
Given: ![]()
Need to prove: The triangle is right-angled
sin2A + sin2B = sin2C
We know, ![]()
So,
![]()
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This is one of the properties of right angled triangle. And it is satisfied here. Hence, the triangle is right angled. [Proved]
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