Seg AD and seg BE are medians of ∆ABC and point G is the centroid. If l (AG) = 5 cm, find l (GD). If l (GE) = 2 cm, find l (BE).
If ∆ABC is a triangle where AD and BE are medians. Both AD and BE intersect at a point G, it is not other than centroid.
Now from the above concept.
G divides AD in 2:1
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GD = AG/2 = 5cm/2 = 2.5 cm
Hence, length of GD=2.5 cm
Similarly, G divides BE in 2:1
e.g. ![]()
GE = 2 cm
Then BG 2 × GE = 2× 2 = 4cm
Now length of BE = BG + GE = 4m + 2cm
Length of BE = 6cm
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