To prove: (f o g) = IR = (g o f).
Formula used: (i) f o g = f(g(x))
(ii) g o f = g(f(x))
Given: (i) f : R → R : f(x) = (2x - 3)
(ii) ![]()
Solution: We have,
f o g = f(g(x))


= x + 3 – 3
= x
= IR
g o f = g(f(x))
![]()
![]()
= ![]()
= x
= IR
Clearly we can see that (f o g) = IR = (g o f) = x
Hence Proved.
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