Q7 of 77 Page 32

For the following probability distribution:

The value of E(X) is


The probability distribution of X is:



We Know that



Therefore,


(-4×0.1)+(-3×0.2)+(-2×0.3)+(-1×0.2)+(0×0.2)


⇒ -0.4-0.6-0.6-0.2


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If X is a random-variable with probability distribution as given below:

The value of k and its variance are


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The probability distribution of a discrete random variable X is given below:

The value of E(X) is


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For the following probability distribution:

















X:



1



2



3



4



P(X):



1/10



1/5



3/10



2/5



The value of E(X2) is


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Let X be a discrete random variable. Then the variance of X is