A bag contains 4 red and 6 black balls. Three balls are drawn at random. Find the probability distribution of the number of red balls.
X represents the number of red balls drawn.
∴ X can take values 0,1,2 or 3
∵ there are total 10 balls
n(S) = total possible ways of selecting 2 balls = ![]()
P(X = 0) = P(selecting no red balls) = ![]()
P(X = 1) = P(selecting 1 red ball and 2 black balls)
= ![]()
P(X = 2) = P(selecting 2 red balls and 1 black ball)
= ![]()
P(X = 3) = P(selecting 3 red balls and 0 black ball)
= ![]()
Now we have pi and xi.
Following table represents the probability distribution of X :

Couldn't generate an explanation.
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