Q10 of 136 Page 28

Write the direction cosines of the line whose cartesian equations are 2x = 3y = –z.

We have


2x = 3y = -z


The equation of the given line can be re-written as,




The direction ratios of the line parallel to AB are proportional to → 3, 2, -6


The direction cosines of the line parallel to AB are proportional to →


, ,


, ,


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