Find the foot of the perpendicular drawn from the point
to the line
Also, find the length of the perpendicular.
Given: - Point with position vector
and equation of line ![]()
Let, PQ be the perpendicular drawn from P (
) to given line whose endpoint/ foot is Q point.
Q is on line
![]()
⇒
is the position vector of Q
Hence,
![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
Since, PQ is perpendicular on line ![]()
Therefore, their Dot product is zero
Compare given line equation with ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ 14λ – 14 = 0
⇒ λ = 1
Hence Position vector of Q by putting the value of λ
![]()
⇒ ![]()
⇒
; Foot of perpendicular
and Distance PQ, putting the value of λ in PQ vector equation, we get
⇒ ![]()
⇒ ![]()
⇒ ![]()
Now, Magnitude of PQ
We know that,
; where x,y,z are coefficient of vector
Hence
⇒ ![]()
⇒ ![]()
⇒
units
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