An object of 5cm tall is placed at a distance of 10cm from a concave mirror of radius of curvature 30cm
i) Find the nature, position and size of the image
ii) Draw the ray diagram to represent the above case.
Given,
Height of object (ho) = 5cm
Object length (u) = -10cm
Radius of curvature (R) =-30 cm
The focal length of the mirror is given by,


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According to mirror formula,
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Hence, the image formed is virtual and behind the mirror.
The magnification is given by
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And the magnification is also given by
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So, the image formed is magnified and erect.
ii) The figure below is the ray diagram of the above case

• C=Centre of curvature
• F=Focus
• f=Focal length
• u=Object length
• v=Image length
• AB=Object height
• A’B’=Image height
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