Solve the differential equation:
.
Or
Solve the differential equation:
;y(0)=0.
Given that ![]()
This differential equation is of the form y’ + P(x)y = Q(x).
To solve such equation, we multiply the entire equation with integration factor
.
Here ![]()
Then integration factor will be
.
Let 1+x2=t
⇒ 2x dx=dt.
![]()
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![]()
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Multiplying (1) with
, we get
![]()
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⇒ ![]()
Integrating both sides
![]()

![]()
=tan-1 x + x + c
y = (1+x2)(tan-1 x + x + c)
OR
Given that ![]()
![]()
Integrating both sides
![]()
![]()
Let 2-ey=t
⇒ eydy=-dt
![]()
or ![]()
![]()
Hence
,
where ![]()
![]()
Or ![]()
![]()
Since bases of both logs are same, therefore the argument must be equal too
![]()
Simplifying this equation, we get
![]()
Since when x=0, y=0, therefore
![]()
or k=1
Hence, ![]()
![]()
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