Solve the differential equation:
, given that y = 0 when x = 1.
OR
Solve the differential equation:
, subject to the initial condition y(0) = 0.
Given equation: ![]()
On-rearranging the term, we get,
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Now, this is a homogenous differential equation of order 1.
Let y = vx and ![]()
Therefore,
![]()
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Integrating both sides, we get,
![]()
Now, we know that,
and ![]()
Therefore,
![]()
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Putting the value of y, we get,

At x = 1, y = 0,
![]()
C = 1
Hence,

![]()
OR
Given Equation: ![]()
Dividing the whole equation by (1 + x2), we get,
![]()
Now, this is a linear equation of the form,
![]()
We know that the solution of this equation is given by,
![]()
Where ![]()
Therefore, for a given equation,
![]()
Let 1 + x2 = t
Differentiating both sides, we get,
2x dx = dt
Therefore,
![]()
![]()
The solution of the equation:
![]()
![]()
![]()
At x = 0, y = 0
Therefore,
![]()
![]()
Hence,
![]()
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