Q14 of 76 Page 929

For each of the following differential equations, find a particular solution satisfying the given condition :

it being given that y = 1 when x = 0.


Rearranging the terms we get:



Integrating both the sides we get:




⇒y - 1 = 2x2 + c


y = 1 when x = 0


⇒ (1) - 1 = 2(0)2 + c


⇒c = 1




Ans:


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