Solve (1 + x2) sec2 y dy + 2x tan y dx = 0, given that
when x = 1.
we have, (1 + x2) sec2 y dy + 2x tan y dx = 0,
Given that,
when x=1
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For ![]()
We have, ![]()
c = 2,
Hence the required particular solution is:-
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