Find the volume of the parallelepiped whose conterminous edges are represented by the vectors
i. ![]()
ii.
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iii. ![]()
iv. ![]()
i. ![]()
Given :
Coterminous edges of parallelopiped are
where,
![]()
![]()
![]()
To Find : Volume of parallelepiped
Formulae :
1) Volume of parallelepiped :
If
are coterminous edges of parallelepiped,
Where,
![]()
![]()
![]()
Then, volume of parallelepiped V is given by,

2) Determinant :

Answer :
Volume of parallelopiped with coterminous edges
![]()
![]()
![]()



![]()
= 1(-1) -1(-2) + 1(3)
= -1+2+3
= 4
Therefore,
![]()
ii.
![]()
Given :
Coterminous edges of parallelopiped are
where,
![]()
![]()
![]()
To Find : Volume of parallelepiped
Formulae :
1) Volume of parallelepiped :
If
are coterminous edges of parallelepiped,
Where,
![]()
![]()
![]()
Then, volume of parallelepiped V is given by,

2) Determinant :

Answer :
Volume of parallelopiped with coterminous edges
![]()
![]()
![]()



![]()
= -3(-36) -7(36) + 5(-24)
= 108 – 252 – 120
= -264
As volume is never negative
Therefore,
![]()
iii. ![]()
Given :
Coterminous edges of parallelopiped are
where,
![]()
![]()
![]()
To Find : Volume of parallelepiped
Formulae :
1) Volume of parallelepiped :
If
are coterminous edges of parallelepiped,
Where,
![]()
![]()
![]()
Then, volume of parallelepiped V is given by,

2) Determinant :

Answer :
Volume of parallelopiped with coterminous edges
![]()
![]()
![]()



![]()
= 1(2) +2(2) + 3(2)
= 2 + 4 + 6
= 12
Therefore,
![]()
iv. ![]()
Given :
Coterminous edges of parallelopiped are
where,
![]()
![]()
![]()
To Find : Volume of parallelepiped
Formulae :
1) Volume of parallelepiped :
If
are coterminous edges of parallelepiped,
Where,
![]()
![]()
![]()
Then, volume of parallelepiped V is given by,

2) Determinant :

Answer :
Volume of parallelopiped with coterminous edges
![]()
![]()
![]()



![]()
= 6(10) + 0 + 0
= 60
Therefore,
![]()
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