Show that the vectors
are coplanar, when
i.
and ![]()
ii.
and ![]()
iii.
and ![]()
i.
and ![]()
Given Vectors :
![]()
![]()
![]()
To Prove : Vectors
are coplanar.
i.e. ![]()
Formulae :
1) Scalar Triple Product:
If
![]()
![]()
![]()
Then,

2) Determinant :

Answer :
For given vectors,
![]()
![]()
![]()

![]()
= 1(3) + 2(-6) + 3(3)
= 3 – 12 +9
= 0
![]()
Hence, the vectors
are coplanar.
Note : For coplanar vectors
,
![]()
ii.
and ![]()
Given Vectors :
![]()
![]()
![]()
To Prove : Vectors
are coplanar.
i.e. ![]()
Formulae :
1) Scalar Triple Product:
If
![]()
![]()
![]()
Then,

2) Determinant :

Answer :
For given vectors,
![]()
![]()
![]()

![]()
= 1(4) – 3(6) + 1(14)
= 4 – 18 + 14
= 0
![]()
Hence, the vectors
are coplanar.
Note : For coplanar vectors
,
![]()
iii.
and ![]()
Given Vectors :
![]()
![]()
![]()
To Prove : Vectors
are coplanar.
i.e. ![]()
Formulae :
1) Scalar Triple Product:
If
![]()
![]()
![]()
Then,

2) Determinant :

Answer :
For given vectors,
![]()
![]()
![]()

![]()
= 2(2) + 1(16) + 2(-10)
= 4 + 16 -20
= 0
![]()
Hence, the vectors
are coplanar.
Note : For coplanar vectors
,
![]()
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