Mark the correct alternative in the following:
If
, then
is equal to
r + r – 10 = 20 ( nCx = nCy ⇒ n = x + y or x = y )
2r – 10 = 20
2r = 30
r = 15
Now,
18Cr = 18C15
18C15 = 18C3
18C3![]()
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