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17. Combinations
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Q1 of 118 Page 17

Mark the correct alternative in the following:

If , then is equal to


r + r – 10 = 20 ( nCx = nCy ⇒ n = x + y or x = y )


2r – 10 = 20


2r = 30


r = 15


Now,


18Cr = 18C15


18C15 = 18C3


18C3

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Questions · 118
17. Combinations
1 1 1 1 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 20 20 20 1 2 3 4 5 5 5 6 7 8 8 8 9 10 11 12 13 14 15 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 30 30 31 32 33 1 2 3 3 3 4 5 6 7 8 9 10 11 1 2 3 4 5 6 7 8 9 10 11 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27
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