Evaluate the following:
35C35
We know that
..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of ![]()
From (1)
⇒ ![]()
⇒ ![]()
We know that 0! = 1
⇒ ![]()
⇒ ![]()
∴ The value of
is 1.
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