Mark the correct alternative in the following :
If the sum of odd numbered terms and the sum of even numbered terms in the expansion of
are A and B respectively, then the value of
is.
Given:

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= A+B

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= A-B
(x2-a2 )n= [(x+a)(x-a)]n
=(x+a)n (x-a)n
= (A+B) (A-B)
=A2-B2
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