Mark the correct alternative in the following:
For any two sets A and B, (A − B)
(B − A) =
(A∖B)⋃(B∖A)=[A⋂B' ]⋃[B⋂A']
=[A⋃(B⋂A' )]⋂[B'⋃(B⋂A' )]
=[(A⋂B)⋃(A⋂A' )]⋂[(B'⋂B)⋃(B'⋂A' )]
=[(A⋂B)⋃ϕ]⋂[ϕ⋃(B'⋂A' )]
=[(A⋂B)]⋂[(B'⋂A' )
=[(A⋂B)]⋂[(B⋃A)' ]
=(B⋃A)'⋂(A⋂B)
=(A⋃B)∖(A⋂B)
Couldn't generate an explanation.
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