Mark the correct alternative in the following:
Suppose A1, A2,...,A30 are thirty sets each having 5 elements and B1, B2,...,Bn are n sets each with 3 elements, let
and each element of S belongs to exactly 10 of the
and exactly 9 of the
, then n is equal to
If elements are not repeated then number of elements in A1⋃A2⋃A3⋃….⋃A30=30*5=150
But, each element of S is in 10 of ![]()
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If elements are not repeated then number of elements in B1⋃B2⋃B3⋃….⋃Bn=3*n
But, each element of S is in
of ![]()
![]()
![]()
∴3× n=15× 9
∴n=45
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