If cot (α + β) = 0, then write the value of sin (α + 2β).
Given: cot(α + β) = 0
∴ ![]()
⇒ cotα.cotβ = 1
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Now,
Sin(α +2β ) = sinα.cos2β + cosα.sin2β
=sin α (2 cos2 β-1)+cos α.2 sin β.cos β
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