Mark the correct alternative in the following:
If
, the
tan2x + 1 = sec2x
sin2x+cos2x= 1
∴ cos2x= 1 - sin2x
Substituting in f(x) we get
1 - sin2x+ tan2x + 1
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Minimum value of
is 0.
∴ f(x)≥ 2.
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