Q28 of 62 Page 1337

The mean and variance of a binomial distribution are 4 and (4/3) respectively. Find P(X≥ 1).

Mean = np = 4


Variance = npq = 4/3


⇒ q =


⇒ p = 1 - =


⇒ n = 6


The probability (X) is


6C1()1()5 + 6C1()1()5 + 6C1()1()5 + 6C1()1()5 + 6C1()1()5 + 6C1()1()5


=


More from this chapter

All 62 →
26

Determine the binomial distribution whose mean is 9 and variance is 6?

 27

Find the binomial distribution whose mean is 5 and variance is 2.5.

 29

For a binomial distribution, the mean is 6 and the standard deviation is . Find the probability of getting 5 successes.

 30

In a binomial distribution, the sum and the product of the mean and the variance are (25/3) and (50/3) respectively. Find the distribution.