For a binomial distribution, the mean is 6 and the standard deviation is
. Find the probability of getting 5 successes.
Mean = np = 6
Variance = npq = 2
⇒ q = ![]()
⇒ p = 1 -
= ![]()
⇒ n = 9
The probability of getting 5 successes,
9C5(
)5(
)4
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