Factorize:64a3+125b3+240a2b+300ab2

Given,64a3 + 125b3 + 240a2b + 300ab2,= (4a)3 + (5b)3 + 60ab (4a + 5b)= (4a)3 + (5b)3 + 3×4a×5b (4a + 5b)= (4a+5b)3= (4a+5b)(4a+5b)(4a+5b)

Q1 of 111 Page 5

Factorize:
64a³+125b³+240a²b+300ab²

Given,

64a³ + 125b³ + 240a²b + 300ab²,

= (4a)³ + (5b)³ + 60ab (4a + 5b)

= (4a)³ + (5b)³ + 3×4a×5b (4a + 5b)

= (4a+5b)³

= (4a+5b)(4a+5b)(4a+5b)

Factorize each of the following expressions:

8a³-b³-4ax+2bx

Simplify

(i)

(ii)

(iii)

Factorize:

125x³-27y³-225x²y+125xy²

Factorize:

x³+1+x²+2x