If 3x=a+b+c, then the value of (x-a)3+(x-b)3+(x-c)3-3(x-a)(x-b)(x-c) is
We have,
= 3x = a+b+c
Let ![]()
So, ![]()
=
[ a +b + c = 3x ] given
= ![]()
Now, ![]()
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