A and B are square matrices of order 3 each, |A| = 2 and |B| = 3. Find |3AB|.
We know that,
|AB| = |A||B|
⇒ |AB| = 2 × 3 = 6
When a matrix of order n is multiplied by a scalar“α”, the determinant of new matrix becomes “αn” times the determinant of original matrix
i.e. |αA| = αn|A|
⇒ |3AB| = 33|AB| = 27(6) = 162
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