Can y = ax +
be a solution of the following differential equation?

If no, find the solution of the D.E. (*).
OR
Check whether the following differential equation is homogeneous or not

Find the general solution of the differential equation using substitution y=vx.
Given,

If,
it should satisfy the above equation
Taking RHS of (*)

![]()
![]()
= y
= LHS
Hence,
is a solution of DE(*)
OR
![]()
[1]
Now,
![]()
Now, for equation to be homogenous, f(x, y) should be homogenous
i.e.
f (zx, zy) = znf(x, y)
Now,
![]()
≠ znf (x, y) for any n
Hence, the given equation is not homogenous
Now, put y = vx
![]()
Therefore [1], becomes
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
Integrating both sides,
![]()
Put ![]()
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.



