Q8 of 50 Page 12

If the area of an isosceles right triangle is 8 cm, what is the perimeter of the triangle?

In right isosceles ∆ABC


Area of triangle =


8 =



(AC)2 = (AB)2 + (BC)2






Perimeter of ∆ABC = AB + BC + CA = 4 + 4 + 4√2 = 8 + 4√2 cm

More from this chapter

All 50 →
6

The sides of a triangle are 11 m, 60 m and 61 m. The altitude to the smallest side is

 7

The sides of a triangle are 11 cm, 15 cm and 16 cm. The altitude to the largest side is

 9

The length of the sides of ΔABC are consecutive intergers. It ΔABC has the same perimeter as an equilateral triangle, triangle with a side of length 9 cm, what is the length of the shortest side of ΔABC?

 10

In figure 12.35, the ratio of AD to DC is 3 to 2. If the area of ΔABC is 40 cm2, what is the area of ΔBDC?