Q10 of 50 Page 12

In figure 12.35, the ratio of AD to DC is 3 to 2. If the area of ΔABC is 40 cm2, what is the area of ΔBDC?

In ∆ABC


AD:DC = 3:2


Area of ∆ABD = =


Area of ∆BDC = =



Area of ∆ABC = area of ∆ABD+ area of ∆BDC = 40 cm2




Therefore area of ∆ABD =


Therefore area of ∆BDC =

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