In Fig. 5.1, the co-efficient of friction between the floor and the body B is 0.1. The co-efficient of friction between the bodies B and A is 0.2. A force F is applied as shown on B. The mass of A is m/2 and of B is m. Which of the following statements are true?

We have given
Let acceleration in body A and B is ‘a’.
Body A will move along with body B by force F till the force of friction between surface of A and B is larger or equal to zero.

Now taking system A+B then acceleration will be
⇒ ![]()
⇒ ![]()
⇒ ![]()
So force on A
⇒ FAB![]()
⇒FAB![]()
⇒FAB![]()
If FABis equal or smaller than f2 then body A will move along with body B.
So f2=FAB or ![]()
…(i)
N=Reaction force by B on A
![]()
[N₂=Normal reaction on B along with A by surface]
…. (ii)
From (i)
so adding this with equation (ii) we can say F
…(iii)
F = 0.45mg Newton is the maximum force on B. so that A and B can move together. So option (e) is correct.
Both bodies can move together if F is less than or equal to 0.45mg Newton.
So options (a) and (b) are also correct and rejects the option (c) as 0.5mg>0.45mg.
For option (d): Minimum force which can move A and B together
⇒Fmin![]()
⇒Fmin![]()
⇒Fmin![]()
Given force in option (d) 0.1mg Newton <0.25mg Newton. So body A and B will not move i.e.
Bodies A and B will remain in rest hence option (d) is also correct.
Couldn't generate an explanation.
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