A 100 kg gun fires a ball of 1kg horizontally from a cliff of height 500m. It falls on the ground at a distance of 400m from the bottom of the cliff. Find the recoil velocity of the gun. (acceleration due to gravity = 10 m s-2)
Given, the height of the cliff is,
Height of the cliff, h=500 m
Mass of the ball, m= 1 kg
Mass of the gun, M=100 kg
Range of the ball, R= 400 m
Acceleration due to gravity, g= 10 m s-2
Let the final velocity of the ball be u and the of the gun be v.
Now we know, time of flight is


And range is given by:
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So, u=400/10 = 40 m s-2
Therefore, the velocity is:
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The recoil velocity of the gun is 0.4 m s-1.
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