Water is flowing at the rate of 15 km/hour through a pipe of diameter 14 cm into a cuboidal pond which is 50 m long and 44 m wide. In what time will the level of water in the pond rise by 21 cm?
Let, the level of water rise by 21 cm is in t hours.
Diameter of a pipe = 14 cm =
m
Radius of the pipe =
m
Volume of water flowing in pipe in 1 hour = πr2h
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= 231 m3
Volume of water flowing in pipe in t hour = 231t m3
Volume of water in pond = l × b × h
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= 462 m3
Volume of water flowing in pipe in t hour = Volume of water
in pond
231 t = 462
t = 2 hours
So, in 2 hours the level of water in pond rise by 21 cm.
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