The angle of elevation of top of a vertical tower from a point on the ground is 60⁰. From another point 10 m vertically above the first, it’s angle of elevation is 30⁰. Find the height of the tower.

Let, h + 10 be the height of the tower.
In ∆ ABC
…(1)
In ∆ ADE
…(2)
From eq.(1) and eq.(2)
3h = h + 10 ⇒ h = 5 m
So, the height of tower is 15 m
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