A capacitor of 4 μ F is connected in a circuit as shown. The internal resistance of the battery is 0.5 Ω. The amount of charge on the capacitor plates will be


In steady state, there will be no current in the capacitor branch
Net resistance of the circuit ![]()
Current drawn from the cell ![]()
Potential drop across two parallel branches
So, charge on the capacitor plates
Under steady state capacitor becomes open circuited therefore whatever Vc (capacitor voltage) you need it is nearly equal to V1
∴ correct answer is 8μC
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