I) Calculate emf and
G for the following cell:
![]()
Given:
and ![]()
II) a) Conductivity of 0.20 mol L-1 solution of KCl is
. Calculate its molar conductivity and degree of dissociation
Given
= 73.5
and
= 76.5
.
b) What type of battery is mercury cell? Why is it more advantageous than dry cell?
I)![]()
Given:
and ![]()
Now, ![]()
n = 2 (2 electrons are getting transferred)
![]()
![]()
![]()
Putting all the values,
![]()
![]()
(Concentrations of Solids is 1 M)
![]()
![]()
![]()
Also,
![]()
![]()
![]()
![]()
II) a) conductivity (K) = ![]()
Concentration (c) = 0.20 mol L-1
Molar conductivity = ![]()
![]()
= 124 ![]()
= 73.5 ![]()
= 76.5
.
![]()
![]()
![]()
![]()
![]()
![]()
b) Mercury cell is a type of primary battery. In primary batteries, the charging reaction occurs only once and after a period of time, the battery becomes dead. Mercury cell is more advantageous than dry cell has a very short life span due to the conversion of zinc to zinc chloride that makes the zinc casing porous. Due to porous casing, the substance inside the cell leaks out and corrodes the metal, reducing the lifetime of the cell.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

