Prove that (1 + tan A – sec A) × (1 + tan A + sec A) = 2 tan A
OR
Prove that 
Taking LHS
(1 + tan A – sec A)(1 + tan A + sec A)
Using (a – b)(a + b) = a2 – b2
= (1 + tan A)2 – sec2A
= 1 + tan2A + 2 tan A – sec2A
= sec2A + 2 tan A – sec2A
= 2 tan A
= RHS
OR
Taking LHS
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= 2 sec2θ
= RHS
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