Prove that
Let us assume, to the contrary,
that is rational. So, we can find integers p and q(q ≠ 0), such that
, where p and q are coprime.
Squaring both sides, we get
..... (i)
⇒ ![]()
⇒ 5 divides q2⇒ 5 divides q
So, p and q have at least 5 as a common factor. But this contradicts the fact that p and q have no common factor. So, our assumption is wrong.
5 is irrational.
5 is irrational, 3 is a rational number.
So, we conclude that 3 + 5 is a rational number.
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