(a) A boy, who we
(a) Mass of the boy = 40 Kg
The efficiency of the boy is 28 %.
Therefore, the total energy utilized by him is 28 % of 21 KJ
0.28 × 21 KJ = 5.88 KJ
Now, according to the conservation of energy,
Loss in energy due to climbing = Gain in potential energy
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(b) If the balls fall through the same height along a frictionless path, their velocity on reaching the ground will be equal. This is according to the law of conservation of energy.
If they fall from a point at a height ‘h’ from the ground, the potential energy at the point is, PE = mgh
The kinetic energy on reaching the ground is, KE = � mv2
Since, PE = KE
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The equation is independent of mass.
Then the ratio of speeds would 1:1:1
(a) We know that - momentum = mass × velocity
A body can only possess velocity if it has kinetic energy and if does not have that energy than velocity = 0, using this value in above mentioned formula
Momentum = mass × 0
Momentum = 0
So, a body cannot have momentum without having energy.
Sometimes even if a body has energy, its momentum can be zero. For example: a brick lying on the roof of a building possesses potential energy but no velocity so momentum will be zero.
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