The areas of three adjacent faces of a cuboid are x, y, and z. If the volume is V, prove that V2 = xyz.
Given,
Areas of three faces of cuboid = ![]()
Let length of cuboid = ![]()
So,
= ![]()
= ![]()
= ![]()
Or we can write ,
= ![]()
If ‘V’ is volume of cuboid = V = ![]()
= ![]()
= ![]()
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