Q26 of 93 Page 10

In Fig. 10.64, BC is a tangent to the circle O. OE bisects AP. Prove that .


Triangle AOP is an isosceles triangle because OA=OP as they are the radius of the circle. We know that radius of the circle is always perpendicular to the tangent at the point of contact.


Here OB is the radius and BC is the tangent and B is the point of contact, Therefore



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