Q16 of 93 Page 10

In Fig. 10.81, AP is a tangent to the circle with centre O such that OP = 4 cm and ∠OPA = 30°. Then, AP =

Given:


OP = 4 cm


∠OPA = 30°



Property: The tangent at a point on a circle is at right angles to the radius obtained by joining center and the point of tangency.


By above property, ∆POA is right-angled at ∠OAP (i.e., ∠OAP = 90°).


Now we know that,



Therefore,






⇒ AP = 2√3 cm


Hence, AP = 2√3 cm

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