If
is the mean of the ten natural numbers, x1, x2, x3,…., x10, show that
(x1-
)+(x2-
)+ ….+(x10-
)= 0.
We have,
= ![]()
x1 + x2 + x3 + …. + x10 = 10
(i)
Now, (x1 -
) + (x2 -
) + …. + (x10 -
)
= (x1 + x2 + …. + x10) – (
+
+ …. + up to 1o terms)
= 10
- 10
[From (i)]
= 0
Therefore, (x1 -
) + (x2 -
) + …. + (x10 -
) = 0
Hence, proved
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